The side of a copper cube is $1 \ m$ at $0^{\circ} C$. What will be the change in its volume,when it is heated to $100^{\circ} C$? $[\alpha_{\text{copper}} = 18 \times 10^{-6} /^{\circ} C]$

  • A
    $45 \times 10^{-4} \ m^3$
  • B
    $54 \times 10^{-4} \ m^3$
  • C
    $34 \times 10^{-4} \ m^3$
  • D
    $64 \times 10^{-4} \ m^3$

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