The slope of a line $L$ is $2$. If $m_1$ and $m_2$ are the slopes of two lines which are inclined at an angle of $\frac{\pi}{6}$ with $L$,then $m_1 + m_2 =$

Statement $(A)$ : The line $2x + y + 6 = 0$ is perpendicular to the line $x - 2y + 5 = 0$ and the second line passes through $(1, 3)$.
Reason $(R)$ : The product of the slopes of perpendicular lines is $-1$.

If the line through the points $(-2, 6)$ and $(4, 8)$ is perpendicular to the line passing through the points $(8, 12)$ and $(x, 24)$,then the value of $x$ is

The angle between the lines $x \cos 30^\circ + y \sin 30^\circ = 3$ and $x \cos 60^\circ + y \sin 60^\circ = 5$ is .....$^\circ$

The angle between the lines $x \cos \alpha_1 + y \sin \alpha_1 = p_1$ and $x \cos \alpha_2 + y \sin \alpha_2 = p_2$ is

The angle between the two lines $y - 2x = 9$ and $x + 2y = -7$ is .....$^o$.