The solution of x + y - 1 = 0 and 2x + 2y - 5 | vedclass

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(B) Given equations are:$1) \, x + y - 1 = 0 \implies x + y = 1$$2) \, 2x + 2y - 5 = 0 \implies 2(x + y) = 5 \implies x + y = 2.5$Comparing the two eq

Vedclass · Accepted Answer

not possible

Vedclass · Answer

(B) Given equations are:$1) \, x + y - 1 = 0 \implies x + y = 1$$2) \, 2x + 2y - 5 = 0 \implies 2(x + y) = 5 \implies x + y = 2.5$Comparing the two equations,we see that $x + y$ cannot be both $1$ and $2.5$ simultaneously.Alternatively,checking the ratio of coefficients:$\frac{a_1}{a_2} = \frac{1}{2}$,$\frac{b_1}{b_2} = \frac{1}{2}$,and $\frac{c_1}{c_2} = \frac{-1}{-5} = \frac{1}{5}$.Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_1}{c_2}$,the lines are parallel and do not intersect.Therefore,the system of equations has no solution.

The solution of $x + y - 1 = 0$ and $2x + 2y - 5 = 0$ is ...........

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