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(C) Given equations are:$x + y - 1 = 0$  --- $(1)$$2x + 2y - 2 = 0$ --- $(2)$Divide equation $(2)$ by $2$:$x + y - 1 = 0$Since both equations are iden

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an infinite set

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(C) Given equations are:$x + y - 1 = 0$  --- $(1)$$2x + 2y - 2 = 0$ --- $(2)$Divide equation $(2)$ by $2$:$x + y - 1 = 0$Since both equations are identical,they represent the same line.For a system of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$,if $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$,the system has infinitely many solutions.Here,$\frac{1}{2} = \frac{1}{2} = \frac{-1}{-2} = \frac{1}{2}$.Therefore,the system has infinitely many solutions,which corresponds to an infinite set.

The solution of $x+y-1=0$ and $2x+2y-2=0$ is ............

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