The solution of the differential equation $\frac{dy}{dx} = (1 + x)(1 + y^2)$ is
- A$y = \tan(x^2 + x + c)$
- B$y = \tan(2x^2 + x + c)$
- C$y = \tan(x^2 - x + c)$
- D$y = \tan\left(\frac{x^2}{2} + x + c\right)$
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