The solution set of x^{2} leq 9 is | vedclass

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(A) Given the inequality $x^{2} \leq 9$. This can be rewritten as $x^{2} - 9 \leq 0$. Factoring the expression,we get $(x - 3)(x + 3) \leq 0$. For the

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$[-3, 3]$

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(A) Given the inequality $x^{2} \leq 9$. This can be rewritten as $x^{2} - 9 \leq 0$. Factoring the expression,we get $(x - 3)(x + 3) \leq 0$. For the product of two factors to be less than or equal to zero,the values of $x$ must lie between the roots of the equation $(x - 3)(x + 3) = 0$. The roots are $x = 3$ and $x = -3$. Testing the intervals,we find that for $x \in [-3, 3]$,the expression $(x - 3)(x + 3) \leq 0$ holds true. Therefore,the solution set is $[-3, 3]$.

The solution set of $x^{2} \leq 9$ is

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