The specific conductance $(\kappa)$ of $0.02 \ M$ aqueous acetic acid solution at $298 \ K$ is $1.65 \times 10^{-4} \ S \ cm^{-1}$. The degree of dissociation of acetic acid is [Given equivalent conductance at infinite dilution of $H^{+} = 349.1 \ S \ cm^{2} \ mol^{-1}$ and $CH_{3}COO^{-} = 40.9 \ S \ cm^{2} \ mol^{-1}$]

For a strong electrolyte,the molar conductivity is given by $\wedge _m = \wedge _m^o - 10 \sqrt{C}$. Calculate $\wedge _m$ at $0.01 \ M$ if its value at $0.16 \ M$ is $200 \ S \ cm^2 \ mol^{-1}$.

The conductivity of $0.02 \ M$ $KCl$ solution is $0.00250 \ \Omega^{-1} \ cm^{-1}$. What is its molar conductivity?

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration $0.1 \, M$ is $100 \, \Omega .$ The conductivity of this solution is $1.29 \, S \, m^{-1}.$ Resistance of the same cell when filled with $0.2 \, M$ of the same solution is $520 \, \Omega .$ The molar conductivity of $0.2 \, M$ solution of electrolyte will be..........$\times 10^{-4} \, S \, m^2 \, mol^{-1}$

For an $HCl$ solution at $25^o C$,the equivalent conductance at infinite dilution is $425 \ \Omega^{-1} \ cm^2 \ eq^{-1}$. The electrical conductivity of the $HCl$ solution is $3.825 \ \Omega^{-1} \ cm^{-1}$. If the degree of dissociation is $90\%$,what is the normality of the solution in $N$?

Write a note on molar conductivity $(\Lambda_{m})$ of a solution.