The specific heat of argon at constant pressu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For an ideal gas,the relation between molar specific heats is $C_p - C_v = R$,where $R$ is the universal gas constant.Since $C_p$ and $C_v$ are gi

Vedclass · Accepted Answer

$\frac{P}{T(C_p-C_v)}$

Vedclass · Answer

(A) For an ideal gas,the relation between molar specific heats is $C_p - C_v = R$,where $R$ is the universal gas constant.Since $C_p$ and $C_v$ are given as specific heats (per unit mass),we use the relation $C_p - C_v = \frac{R}{M}$,where $M$ is the molar mass of the gas.Thus,$R = M(C_p - C_v)$.The ideal gas equation is $PV = nRT$,where $n = \frac{m}{M}$ is the number of moles.Substituting $n$ and $R$ into the equation: $PV = \frac{m}{M} \cdot M(C_p - C_v) \cdot T$.Simplifying,we get $PV = m(C_p - C_v)T$.Since density $\rho = \frac{m}{V}$,we can rewrite the equation as $P = \frac{m}{V}(C_p - C_v)T$.Therefore,$\rho = \frac{P}{(C_p - C_v)T}$.

The specific heat of argon at constant pressure and constant volume are $C_p$ and $C_v$ respectively. Its density $\rho$ at $N.T.P.$ will be: [Where $P$ and $T$ are pressure and temperature respectively at $N.T.P.$]

Similar Questions

When a monoatomic gas is heated at constant pressure,what fraction of the heat energy supplied is used to increase the internal energy?

The molar specific heat of an ideal gas at constant pressure and constant volume is $C_p$ and $C_v$ respectively. If $R$ is the universal gas constant and the ratio of $C_p$ to $C_v$ is $\gamma$,then $C_v$ is equal to:

For a diatomic gas,write the value of the ratio of $C_P$ and $C_V$.

$A$ cylinder of fixed capacity of $44.8 \, L$ contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of the gas in the cylinder by $20.0^{\circ} C$ will be .............. $J$ (Given gas constant $R = 8.3 \, J \, K^{-1} \, mol^{-1}$).

What is the significance of the heat capacity ratio $\gamma = \frac{C_{P}}{C_{V}}$ for a gas?

Vedclass Test Series

Exam Paper Generator

Online Exam Module