The speed of the electron (in ms^{-1}) in the | vedclass

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(C) The velocity of an electron in the $n^{th}$ orbit of a hydrogen-like atom is given by the formula: $v = 2.18 	imes 10^6 	imes \frac{Z}{n} \ ms^{

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$7.26 	imes 10^5$

Vedclass · Answer

(C) The velocity of an electron in the $n^{th}$ orbit of a hydrogen-like atom is given by the formula: $v = 2.18 	imes 10^6 	imes \frac{Z}{n} \ ms^{-1}$.For a hydrogen atom, the atomic number $Z = 1$.For the third orbit, the principal quantum number $n = 3$.Substituting these values into the formula:$v = 2.18 	imes 10^6 	imes \frac{1}{3} \ ms^{-1}$.$v = 0.7266 	imes 10^6 \ ms^{-1}$.$v = 7.26 	imes 10^5 \ ms^{-1}$.Therefore, option $(C)$ is the correct answer.

The speed of the electron (in $ms^{-1}$) in the third orbit of a hydrogen atom is approximately (mass of electron $= 9.1 \times 10^{-31} \ kg$).

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