The spin only magnetic moment (mu) value (B.M | vedclass

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(A) The strongest oxidising agent among the given compounds is $Mn_2O_3$ due to the high reduction potential of the $Mn^{3+}/Mn^{2+}$ couple $(E^{\cir

Vedclass · Accepted Answer

$5$

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(A) The strongest oxidising agent among the given compounds is $Mn_2O_3$ due to the high reduction potential of the $Mn^{3+}/Mn^{2+}$ couple $(E^{\circ} = +1.57 \ V)$.In $Mn_2O_3$,the oxidation state of $Mn$ is $+3$.The electronic configuration of $Mn^{3+}$ is $[Ar] 3d^4$.The number of unpaired electrons $(n)$ is $4$.The spin-only magnetic moment is calculated as $\mu = \sqrt{n(n+2)} \ B.M.$$\mu = \sqrt{4(4+2)} \ B.M. = \sqrt{24} \ B.M. \approx 4.89 \ B.M.$The nearest integer value is $5$.

The spin only magnetic moment $(\mu)$ value $(B.M.)$ of the compound with strongest oxidising power among $Mn_2O_3$,$TiO$,and $VO$ is $....$ $B.M.$ (Nearest integer).

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