The standard cell potential of Zn|Zn^{2+}_{(a | vedclass

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(B) The cell reaction is: $Zn_{(s)} + Cu^{2+}_{(aq)} \rightarrow Zn^{2+}_{(aq)} + Cu_{(s)}$.Here,the number of electrons transferred,$n = 2$.The stand

Vedclass · Accepted Answer

$212.30$

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(B) The cell reaction is: $Zn_{(s)} + Cu^{2+}_{(aq)} ightarrow Zn^{2+}_{(aq)} + Cu_{(s)}$.Here,the number of electrons transferred,$n = 2$.The standard cell potential,$E^0_{cell} = 1.10 \, V$.The maximum work $(W_{max})$ obtained from a cell is equal to the decrease in Gibbs free energy $(-\Delta G^0)$.Formula: $W_{max} = nFE^0_{cell}$.Substituting the values: $W_{max} = 2 	imes 96500 \, C/mol 	imes 1.10 \, V$.$W_{max} = 212300 \, J/mol$.Converting to $kJ$: $W_{max} = \frac{212300}{1000} \, kJ = 212.30 \, kJ$.

The standard cell potential of $Zn|Zn^{2+}_{(aq)}||Cu^{2+}_{(aq)}|Cu$ cell is $1.10 \, V$. The maximum work obtained by this cell will be ............. $kJ$.

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