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(A) Let the initial strength of the school in $2000$ be $100$. In $2001$ (first year),there is an increase of $10 \%$: Strength $= 100 + (10 \% 	ext{

Vedclass · Accepted Answer

Increased by $8.9 \%$

Vedclass · Answer

(A) Let the initial strength of the school in $2000$ be $100$. In $2001$ (first year),there is an increase of $10 \%$: Strength $= 100 + (10 \% 	ext{ of } 100) = 100 + 10 = 110$. In $2002$ (second year),there is a decrease of $10 \%$ on the new strength: Strength $= 110 - (10 \% 	ext{ of } 110) = 110 - 11 = 99$. In $2003$ (third year),there is an increase of $10 \%$ on the strength of $2002$: Strength $= 99 + (10 \% 	ext{ of } 99) = 99 + 9.9 = 108.9$. Comparing the strength in $2003$ $(108.9)$ with the strength in $2000$ $(100)$: Percentage change $= \frac{108.9 - 100}{100} 	imes 100 \% = 8.9 \%$. Since the result is positive,the strength increased by $8.9 \%$.

The strength of a school increases and decreases in every alternate year by $10 \%$. It started with an increase in $2000$. Then the strength of the school in $2003$ as compared to that in $2000$ was

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