The structure of D-(+)-glucose is given. What | vedclass

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(A) $L-(-)$-glucose is the enantiomer of $D-(+)$-glucose. An enantiomer is a non-superimposable mirror image of the original molecule. To obtain the m

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(A) $L-(-)$-glucose is the enantiomer of $D-(+)$-glucose. An enantiomer is a non-superimposable mirror image of the original molecule. To obtain the mirror image, all chiral centers must have their configurations inverted. In the Fischer projection of $D-(+)$-glucose, the $-OH$ groups are at $C-2$ (right), $C-3$ (left), $C-4$ (right), and $C-5$ (right). In $L-(-)$-glucose, these positions are inverted: $C-2$ (left), $C-3$ (right), $C-4$ (left), and $C-5$ (left). Comparing this to the given options, option $A$ represents the correct mirror image structure.

The structure of $D-(+)$-glucose is given. What is the structure of $L-(-)$-glucose?

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