The sum of the coordination number and the ox | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the oxidation state of metal $M$ be $x$.The complex is $[M(en)_2(C_2O_4)]Cl$. The charge on $en$ is $0$,the charge on $C_2O_4^{2-}$ is $-2$,an

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(D) Let the oxidation state of metal $M$ be $x$.The complex is $[M(en)_2(C_2O_4)]Cl$. The charge on $en$ is $0$,the charge on $C_2O_4^{2-}$ is $-2$,and the charge on the complex ion is $+1$ (since $Cl$ is $-1$).$x + 2(0) + 1(-2) = +1$$x - 2 = 1$$x = +3$Thus,the oxidation number of $M$ is $3$.Now,for the coordination number:$en$ (ethylenediamine) is a bidentate ligand,and $C_2O_4^{2-}$ (oxalate) is also a bidentate ligand.Coordination Number $(C.N.) = (2 	imes 2) + (1 	imes 2) = 4 + 2 = 6$.The sum of the coordination number and the oxidation number is $6 + 3 = 9$.

The sum of the coordination number and the oxidation number of the metal $M$ in the complex $[M(en)_2(C_2O_4)]Cl$ (where $en$ is ethylenediamine) is:

Similar Questions

Sodium thiosulphate is used to remove the unexposed $AgBr$ from photographic films by forming a complex. In this complex of silver,the coordination number of silver is

What is the coordination number of cobalt in $[Co(NH_3)_3Cl_3]$?

Metals have the tendency to lose electrons to form cations. When $Zn$ is added to $NaOH$,a complex is formed. In this complex,$Zn$ is present in:

An aqueous solution of $1 \ mol$ of the coordination compound $[Co(NH_3)_5Cl_3]$ gives $3 \ mol$ of ions. If $1 \ mol$ of the same compound reacts with $2 \ mol$ of $AgNO_3$ to produce $2 \ mol$ of $AgCl_{(s)}$,what is the correct formula of the coordination compound?

The coordination number of $Cu$ in $[Cu(H_2O)_4]^{2+}$ is ...... .

Vedclass Test Series

Exam Paper Generator

Online Exam Module