The sum of the first $n$ terms of an $A.P.$ is given by $S_{n} = 3n^{2} + 5n$. Find the $n^{th}$ term of the $A.P.$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The $n^{th}$ term of an $A.P.$ is given by the formula $a_{n} = S_{n} - S_{n-1}$ for $n > 1$.
Given $S_{n} = 3n^{2} + 5n$.
Then $S_{n-1} = 3(n-1)^{2} + 5(n-1) = 3(n^{2} - 2n + 1) + 5n - 5 = 3n^{2} - 6n + 3 + 5n - 5 = 3n^{2} - n - 2$.
Now,$a_{n} = (3n^{2} + 5n) - (3n^{2} - n - 2) = 3n^{2} + 5n - 3n^{2} + n + 2 = 6n + 2$.
For $n = 1$,$a_{1} = S_{1} = 3(1)^{2} + 5(1) = 8$.
Thus,the $n^{th}$ term is $a_{n} = 6n + 2$ for $n \geq 1$.

Explore More

Similar Questions

The $n^{th}$ term of an $A.P.$ is given by $T_n = 4n + 3$. Find the sum of the first $60$ terms of the $A.P.$

Find the sum of first $n$ terms of the $A.P.$ $6, 2, -2, \ldots$

Find the sum:
$1+(-2)+(-5)+(-8)+\ldots+(-236)$

Find the sum of the first $40$ positive integers divisible by $6$.

Difficult
View Solution

In a school,students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees,that each section of each class will plant,will be the same as the class,in which they are studying,e.g.,a section of Class $I$ will plant $1$ tree,a section of Class $II$ will plant $2$ trees and so on till Class $XII$. There are three sections of each class. How many trees will be planted by the students?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo