The sum of five consecutive even numbers of s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the five consecutive even numbers of set-$A$ be $x, x+2, x+4, x+6,$ and $x+8$.According to the question,their sum is $220$:$x + (x+2) + (x+4)

Vedclass · Accepted Answer

$220$

Vedclass · Answer

(D) Let the five consecutive even numbers of set-$A$ be $x, x+2, x+4, x+6,$ and $x+8$.According to the question,their sum is $220$:$x + (x+2) + (x+4) + (x+6) + (x+8) = 220$$5x + 20 = 220$$5x = 200$$x = 40$.So,the lowest number of set-$A$ is $40$.Now,consider a different set of five consecutive numbers. Let the lowest number be $y$. The second lowest number is $y+1$.According to the problem,the second lowest number is $37$ less than double the lowest number of set-$A$:$y+1 = (2 	imes 40) - 37$$y+1 = 80 - 37 = 43$$y = 42$.The five consecutive numbers are $42, 43, 44, 45,$ and $46$.Their sum is $42 + 43 + 44 + 45 + 46 = 220$.

The sum of five consecutive even numbers of set-$A$ is $220$. What is the sum of a different set of five consecutive numbers whose second lowest number is $37$ less than double the lowest number of set-$A$?

Similar Questions

$\frac{16}{24} + \frac{4}{10} - \frac{1}{6} = ?$

If $16 \%$ of $40 \%$ of a number is $8,$ the number is

If the two digits of the age of Mr. Manoj are reversed,then the new age so obtained is the age of his wife. $\frac{1}{11}$ of the sum of their ages is equal to the difference between their ages. If Mr. Manoj is older than his wife,then find the difference between their ages.

$0.01024 \times (0.4)^{9} = (0.4)^{?} \times (0.0256)^{3}$

$(0.88 \times 880 \div 8) \times 6 = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module