frac{16}{24} + frac{4}{10} - frac{1}{6} = ? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) First,simplify the fractions where possible: $\frac{16}{24} = \frac{2}{3}$.Now the expression is $\frac{2}{3} + \frac{4}{10} - \frac{1}{6}$.Simpli

Vedclass · Accepted Answer

$\frac{9}{10}$

Vedclass · Answer

(A) First,simplify the fractions where possible: $\frac{16}{24} = \frac{2}{3}$.Now the expression is $\frac{2}{3} + \frac{4}{10} - \frac{1}{6}$.Simplify $\frac{4}{10}$ to $\frac{2}{5}$.So,the expression becomes $\frac{2}{3} + \frac{2}{5} - \frac{1}{6}$.The least common multiple $(LCM)$ of $3, 5,$ and $6$ is $30$.Convert each fraction to have a denominator of $30$:$\frac{2 	imes 10}{3 	imes 10} + \frac{2 	imes 6}{5 	imes 6} - \frac{1 	imes 5}{6 	imes 5} = \frac{20}{30} + \frac{12}{30} - \frac{5}{30}$.Combine the numerators: $\frac{20 + 12 - 5}{30} = \frac{27}{30}$.Simplify the fraction by dividing by $3$: $\frac{27 \div 3}{30 \div 3} = \frac{9}{10}$.

$\frac{16}{24} + \frac{4}{10} - \frac{1}{6} = ?$

Similar Questions

If the sum and difference of two numbers are $20$ and $8$ respectively,then the difference of their squares is

How many $3$-digit numbers are completely divisible by $6$?

$A$ number,when divided by $729$,leaves a remainder of $56$. What will be the remainder if the same number is divided by $27$?

$72 \%$ of $390 + 28 \%$ of $165 = (x - 3)$

If $a$ and $b$ are odd numbers,then which of the following is even?

Vedclass Test Series

Exam Paper Generator

Online Exam Module