When two dice are thrown,what is the probabil | vedclass

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(A) When two dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $E_1$ be the event that the sum is $6$. The outcome

Vedclass · Accepted Answer

$\frac{11}{36}$

Vedclass · Answer

(A) When two dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $E_1$ be the event that the sum is $6$. The outcomes are $(1,5), (5,1), (2,4), (4,2), (3,3)$. Thus,$n(E_1) = 5$.Let $E_2$ be the event that the sum is $7$. The outcomes are $(1,6), (6,1), (2,5), (5,2), (3,4), (4,3)$. Thus,$n(E_2) = 6$.Since these events are mutually exclusive,the total number of favorable outcomes is $n(E) = n(E_1) + n(E_2) = 5 + 6 = 11$.The required probability is $P(E) = \frac{n(E)}{n(S)} = \frac{11}{36}$.

When two dice are thrown,what is the probability that the sum of the numbers appearing on them is $6$ or $7$?

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