The sum of the bond orders of O_2^{2+}, O_2^{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Using Molecular Orbital Theory $(MOT)$,the electronic configuration and properties are as follows:$O_2^{2+}$: Bond order = $3$,Unpaired electrons

Vedclass · Accepted Answer

$10, 4$

Vedclass · Answer

(A) Using Molecular Orbital Theory $(MOT)$,the electronic configuration and properties are as follows:$O_2^{2+}$: Bond order = $3$,Unpaired electrons = $0$$O_2^{2-}$: Bond order = $1$,Unpaired electrons = $0$$O_2^{+}$: Bond order = $2.5$,Unpaired electrons = $1$$O_2^{-}$: Bond order = $1.5$,Unpaired electrons = $1$$O_2$: Bond order = $2$,Unpaired electrons = $2$Sum of bond orders = $3 + 1 + 2.5 + 1.5 + 2 = 10$Sum of unpaired electrons = $0 + 0 + 1 + 1 + 2 = 4$Therefore,the correct answer is $10, 4$.

The sum of the bond orders of $O_2^{2+}, O_2^{2-}, O_2^{+}, O_2^{-}, O_2$ and the sum of the unpaired electrons present in them respectively are

Similar Questions

The correct sequence of bond order is

Write the important conditions required for the linear combination of atomic orbitals to form molecular orbitals.

Observe the following molecules: $C_2, N_2, O_2, F_2$. Which one of the following statements is correct for the above molecules?

Which one of the following sketches is not correctly matched?

In dinitrogen tetroxide $(N_2O_4)$,there:

Vedclass Test Series

Exam Paper Generator

Online Exam Module