The sun is rotating about its own axis. The spectral lines emitted from the two ends of its equator,for an observer on the earth,will show

In the spectrum of light of a luminous heavenly body,the wavelength of a spectral line is measured to be $4747 \ \mathring{A}$,while the actual wavelength of the line is $4700 \ \mathring{A}$. The relative velocity of the heavenly body with respect to the Earth will be (velocity of light is $3 \times 10^8 \ m/s$).

$A$ spectral line $\lambda = 5000\ \mathring A$ in the light coming from a distant star is observed as $5200\ \mathring A$. What will be the recession velocity of the star?

The wavelength of light from a star is $0.4\%$ more than the corresponding wavelength on the Earth. The velocity of the star with respect to the Earth is:

$A$ star emitting light of wavelength $5896 \ \mathring{A}$ is moving away from the earth with a speed of $3600 \ km/s$. The wavelength of light observed on earth will be:
($c = 3 \times 10^8 \ m/s$ is the speed of light)

$A$ light source approaches the observer with velocity $0.8 c$. The Doppler shift for the light of wavelength $5500 \ \mathring{A}$ is.....$\mathring{A}$.