The thermo-emf of a hypothetical thermocouple | vedclass

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(D) The thermo-emf $E$ is given by $E = a	heta + b	heta^2$. The thermoelectric power $P$ is defined as the rate of change of thermo-emf with respect

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None of these

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(D) The thermo-emf $E$ is given by $E = a	heta + b	heta^2$. The thermoelectric power $P$ is defined as the rate of change of thermo-emf with respect to temperature: $P = \frac{dE}{d	heta} = a + 2b	heta$. The neutral temperature $T_n$ is the temperature at which the thermoelectric power becomes zero. Setting $P = 0$,we get $a + 2bT_n = 0$. Therefore,$T_n = -\frac{a}{2b}$. Given the ratio $a/b = 700^{\circ}C$,we substitute this into the expression: $T_n = -\frac{700}{2} = -350^{\circ}C$. Since $-350^{\circ}C$ is not among the given options,the correct choice is $D$.

The thermo-emf of a hypothetical thermocouple varies with the temperature $\theta$ of the hot junction as $E = a\theta + b\theta^2$ in volts,where the ratio $a/b$ is $700^{\circ}C$. If the cold junction is kept at $0^{\circ}C$,then the neutral temperature is:

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