The thickness of a metallic tube is 5 , mm an | vedclass

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(C) Given: Thickness of the tube = $5 \, mm = 0.5 \, cm$. Inner radius $(r)$ = $10 \, cm / 2 = 5 \, cm$. Length $(h)$ = $70 \, cm$. Outer radius $(R)$

Vedclass · Accepted Answer

$9240$

Vedclass · Answer

(C) Given: Thickness of the tube = $5 \, mm = 0.5 \, cm$. Inner radius $(r)$ = $10 \, cm / 2 = 5 \, cm$. Length $(h)$ = $70 \, cm$. Outer radius $(R)$ = $r + 	ext{thickness} = 5 \, cm + 0.5 \, cm = 5.5 \, cm$. Volume of the metal = $\pi(R^2 - r^2)h = \frac{22}{7} 	imes ((5.5)^2 - (5)^2) 	imes 70 = 22 	imes (30.25 - 25) 	imes 10 = 22 	imes 5.25 	imes 10 = 1155 \, cm^3$. Mass = $	ext{Volume} 	imes 	ext{Density} = 1155 \, cm^3 	imes 8 \, g/cm^3 = 9240 \, g$.

The thickness of a metallic tube is $5 \, mm$ and the inner diameter of the tube is $10 \, cm$. Find the mass of a $70 \, cm$ long tube,if the density of the metal is $8 \, g/cm^3$. (in $g$)

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