The third term of a G.P. is the square of the | vedclass

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(C) Let the first term be $a$ and the common ratio be $r$.Given that the third term is the square of the first term: $ar^2 = a^2$.Since $a 
eq 0$,we

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$128$

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(C) Let the first term be $a$ and the common ratio be $r$.Given that the third term is the square of the first term: $ar^2 = a^2$.Since $a 
eq 0$,we have $a = r^2$.Given the second term is $8$: $ar = 8$.Substituting $a = r^2$ into the equation $ar = 8$,we get $(r^2)r = 8$,which implies $r^3 = 8$,so $r = 2$.Then $a = r^2 = 2^2 = 4$.The $6^{th}$ term is given by $T_6 = ar^5$.$T_6 = 4 	imes 2^5 = 4 	imes 32 = 128$.

The third term of a $G.P.$ is the square of the first term. If the second term is $8$,then the $6^{th}$ term is:

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