The torque on a bar magnet due to the earth's | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The torque $	au$ acting on a bar magnet of magnetic moment $M$ placed in an external magnetic field $B$ is given by the formula $	au = MB \sin \

Vedclass · Accepted Answer

Perpendicular to the field of the earth

Vedclass · Answer

(A) The torque $	au$ acting on a bar magnet of magnetic moment $M$ placed in an external magnetic field $B$ is given by the formula $	au = MB \sin 	heta$,where $	heta$ is the angle between the magnetic axis and the magnetic field.For the earth's magnetic field,the torque is $	au = M B_H \sin 	heta$,where $B_H$ is the horizontal component of the earth's magnetic field.The torque $	au$ is maximum when $\sin 	heta$ is maximum,which occurs at $	heta = 90^{\circ}$.Therefore,the torque is maximum when the axis of the magnet is perpendicular to the earth's magnetic field.

The torque on a bar magnet due to the earth's magnetic field is maximum when the axis of the magnet is

Similar Questions

Write the analogy between electrostatics and magnetism.

$A$ magnetised wire of magnetic moment $3.14 \, A-m^2$ is bent in the form of a semi-circle. The new magnetic moment will be.....$A-m^2$

The force between two unit pole strengths placed at a distance of $1 \, m$ is:

If a piece of metal is thought to be a magnet,which one of the following observations would offer conclusive evidence?

$A$ thin rod of length $L$ has magnetic moment $M$ when magnetised. If the rod is bent into a semicircular arc,what is the magnetic moment in the new shape?

Vedclass Test Series

Exam Paper Generator

Online Exam Module