The total energy of an electron in an orbit o | vedclass

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(C) For an electron in a hydrogen atom,the kinetic energy $(K.E.)$ is given by $K.E. = \frac{kZe^2}{2r}$.The potential energy $(P.E.)$ is given by $P.

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$2 E$

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(C) For an electron in a hydrogen atom,the kinetic energy $(K.E.)$ is given by $K.E. = \frac{kZe^2}{2r}$.The potential energy $(P.E.)$ is given by $P.E. = -\frac{kZe^2}{r}$.The total energy $(E)$ is the sum of kinetic energy and potential energy: $E = K.E. + P.E.$Substituting the expressions: $E = \frac{kZe^2}{2r} - \frac{kZe^2}{r} = -\frac{kZe^2}{2r}$.Comparing the expression for total energy $(E)$ and potential energy $(P.E.)$:$E = \frac{P.E.}{2}$.Therefore,$P.E. = 2E$.

The total energy of an electron in an orbit of a hydrogen atom is $E$. The potential energy of the electron in the same orbit is:

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