The total energy of an electron in the $n^{th}$ stationary orbit of the hydrogen atom can be obtained by
- A$E_{n} = -13.6 \times n^{2} \; eV$
- B$E_{n} = \frac{13.6}{n^{2}} \; eV$
- C$E_{n} = -\frac{13.6}{n^{2}} \; eV$
- D$E_{n} = 13.6 \times n^{2} \; eV$
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