The total number of octahedral void(s) per at | vedclass

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(C) In a cubic close packed $(ccp)$ or face-centered cubic $(fcc)$ structure,the number of atoms per unit cell is $Z = 4$.There is one octahedral void

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$1$

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(C) In a cubic close packed $(ccp)$ or face-centered cubic $(fcc)$ structure,the number of atoms per unit cell is $Z = 4$.There is one octahedral void at the body center of the cube and $12$ octahedral voids at the edges,each shared by $4$ unit cells.Number of octahedral voids at the body center $= 1$.Number of octahedral voids at the edges $= 12 	imes \frac{1}{4} = 3$.Total number of octahedral voids per unit cell $= 1 + 3 = 4$.Since there are $4$ atoms per unit cell,the number of octahedral voids per atom $= \frac{4}{4} = 1$.

The total number of octahedral void$(s)$ per atom present in a cubic close packed structure is

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