(B) Let $a = 0.67$ and $b = 0.33$.The given expression is in the form $\frac{a^3 - b^3}{a^2 + ab + b^2}$.Using the algebraic identity $a^3 - b^3 = (a

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(B) Let $a = 0.67$ and $b = 0.33$.The given expression is in the form $\frac{a^3 - b^3}{a^2 + ab + b^2}$.Using the algebraic identity $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$,we can simplify the expression:$\frac{(a - b)(a^2 + ab + b^2)}{a^2 + ab + b^2} = a - b$.Substituting the values of $a$ and $b$ back into the simplified expression:$a - b = 0.67 - 0.33 = 0.34$.

Competitive Quantitative Aptitude Number system Simplification

Medium

The value of $\frac{(0.67 \times 0.67 \times 0.67)-(0.33 \times 0.33 \times 0.33)}{(0.67 \times 0.67)+(0.67 \times 0.33)+(0.33 \times 0.33)}$ is:

A
$3.4$
B
$0.34$
C
$11$
D
$1.1$

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The value of $\frac{(0.67 \times 0.67 \times 0.67)-(0.33 \times 0.33 \times 0.33)}{(0.67 \times 0.67)+(0.67 \times 0.33)+(0.33 \times 0.33)}$ is:

Similar Questions

What will come in the place of the question mark $(?)$ in the following expression?$\frac{343 \times 49}{216 \times 16 \times 81} = ?$

If $2994 \div 14.5 = 172$,then $29.94 \div 1.45 = ?$

$92 \times 576 \div 2 \sqrt{1296} = (?)^{3} + \sqrt{49}$

If the square of the sum of three positive consecutive natural numbers exceeds the sum of their squares by $292$,then what is the largest of the three numbers?

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What will come in the place of the question mark $(?)$ in the following expression?
$\frac{343 \times 49}{216 \times 16 \times 81} = ?$