The value of frac{cot 54^circ}{tan 36^circ} + | vedclass

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Question

(A) We use the trigonometric identities: $	an(90^\circ - 	heta) = \cot 	heta$ and $\cot(90^\circ - 	heta) = 	an 	heta$.Given expression: $\frac{

Vedclass · Accepted Answer

$2$

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(A) We use the trigonometric identities: $	an(90^\circ - 	heta) = \cot 	heta$ and $\cot(90^\circ - 	heta) = 	an 	heta$.Given expression: $\frac{\cot 54^\circ}{	an 36^\circ} + \frac{	an 20^\circ}{\cot 70^\circ}$.Step $1$: Convert the denominator of the first term using $	an 36^\circ = 	an(90^\circ - 54^\circ) = \cot 54^\circ$.Step $2$: Convert the denominator of the second term using $\cot 70^\circ = \cot(90^\circ - 20^\circ) = 	an 20^\circ$.Step $3$: Substitute these values into the expression:$\frac{\cot 54^\circ}{\cot 54^\circ} + \frac{	an 20^\circ}{	an 20^\circ} = 1 + 1 = 2$.

The value of $\frac{\cot 54^\circ}{\tan 36^\circ} + \frac{\tan 20^\circ}{\cot 70^\circ}$ is

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