cos y cos left( frac{pi}{2} - x right) - cos | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) આપેલ પદાવલિ: $E = \cos y \cos \left( \frac{\pi}{2} - x \right) - \cos \left( \frac{\pi}{2} - y \right) \cos x + \sin y \cos \left( \frac{\pi}{2} -

Vedclass · Accepted Answer

$x = n\pi - \frac{\pi}{4} + y, (n \in I)$

Vedclass · Answer

(D) આપેલ પદાવલિ: $E = \cos y \cos \left( \frac{\pi}{2} - x ight) - \cos \left( \frac{\pi}{2} - y ight) \cos x + \sin y \cos \left( \frac{\pi}{2} - x ight) + \cos x \sin \left( \frac{\pi}{2} - y ight)$.નિત્યસમ $\cos \left( \frac{\pi}{2} - 	heta ight) = \sin 	heta$ અને $\sin \left( \frac{\pi}{2} - 	heta ight) = \cos 	heta$ નો ઉપયોગ કરતા:$E = \cos y \sin x - \sin y \cos x + \sin y \sin x + \cos x \cos x$.$E = \sin(x - y) + \cos(x - y)$.$E = 0$ માટે,$\sin(x - y) + \cos(x - y) = 0$.$\Rightarrow \sin(x - y) = -\cos(x - y)$.$\Rightarrow 	an(x - y) = -1$.$\Rightarrow x - y = n\pi - \frac{\pi}{4}$.$\Rightarrow x = n\pi - \frac{\pi}{4} + y$,જ્યાં $n \in I$.

$\cos y \cos \left( \frac{\pi}{2} - x \right) - \cos \left( \frac{\pi}{2} - y \right) \cos x + \sin y \cos \left( \frac{\pi}{2} - x \right) + \cos x \sin \left( \frac{\pi}{2} - y \right)$ ની કિંમત શૂન્ય થાય,જો

Similar Questions

$2(\sin^6 \theta + \cos^6 \theta) - 3(\sin^4 \theta + \cos^4 \theta) + 1$ ની કિંમત શોધો.

$\cos (270^\circ + \theta )\,\cos (90^\circ - \theta ) - \sin (270^\circ - \theta )\,\cos \theta $ નું મૂલ્ય શું છે?

$\frac{{\cos 12^\circ - \sin 12^\circ }}{{\cos 12^\circ + \sin 12^\circ }} + \frac{{\sin 147^\circ }}{{\cos 147^\circ }} = $

$\left( \frac{\sin 2A}{1 + \cos 2A} \right) \left( \frac{\cos A}{1 + \cos A} \right) = $

જો $2\tan A = 3\tan B$ હોય,તો $\frac{\sin 2B}{5 - \cos 2B}$ ની કિંમત કેટલી થાય?

Vedclass Test Series

Exam Paper Generator

Online Exam Module