Class 12Mathematics3-4. Matrices and DeterminantsExpansion of determinants, Solution of equation in the form of determinants and area of triangle and Equation of Line
Difficult$\left|\begin{array}{lll}\sin ^2 14^{\circ} & \sin ^2 66^{\circ} & \tan 135^{\circ} \\ \sin ^2 66^{\circ} & \tan 135^{\circ} & \sin ^2 14^{\circ} \\ \tan 135^{\circ} & \sin ^2 14^{\circ} & \sin ^2 66^{\circ}\end{array}\right|$ का मान ज्ञात कीजिए।
- A$0$
- B$1$
- C$2$
- D$-1$
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Similar Questions
$\left| \begin{array}{ccc} x & 3x + 2 & 2x - 1 \\ 2x - 1 & 4x & 3x + 1 \\ 7x - 2 & 17x + 6 & 12x - 1 \end{array} \right| = 0$ को संतुष्ट करने वाले $x$ के वास्तविक मानों की संख्या है
यदि $\left[\begin{array}{ccc}1 & -1 & x \\ 1 & x & 1 \\ x & -1 & 1\end{array}\right]$ का व्युत्क्रम (inverse) संभव नहीं है,तो $x$ का वास्तविक मान ज्ञात कीजिए।
यदि $2\left|\begin{array}{ll}\sin ( A + B ) & \cos ( A + B ) \\ \cos ( A - B ) & \sin ( A - B )\end{array}\right|+\sqrt{3}= 0$ है,तो $A =$ . . . . . . .
$\lambda$ के उन भिन्न मानों का योग ज्ञात कीजिए जिनके लिए समीकरण निकाय
$(\lambda-1) x+(3 \lambda+1) y+2 \lambda z=0$
$(\lambda-1) x+(4 \lambda-2) y+(\lambda+3) z=0$
$2 x+(3 \lambda+1) y+3(\lambda-1) z=0$
के अशून्य हल हैं।
$(\lambda-1) x+(3 \lambda+1) y+2 \lambda z=0$
$(\lambda-1) x+(4 \lambda-2) y+(\lambda+3) z=0$
$2 x+(3 \lambda+1) y+3(\lambda-1) z=0$
के अशून्य हल हैं।
DifficultJEE MAIN 2020
View Solutionसारणिक का मान ज्ञात कीजिए: $\left|\begin{array}{ccc}1 & a & b \\ 1 & a+b & b \\ 1 & a & a+b\end{array}\right| = $ . . . . . . .
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