The variation of anode current (I_p) in a tri | vedclass

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Question

(D) The mutual conductance $(g_m)$ is defined as the ratio of the change in anode current $(\Delta I_p)$ to the change in grid potential $(\Delta V_g)

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(D) The mutual conductance $(g_m)$ is defined as the ratio of the change in anode current $(\Delta I_p)$ to the change in grid potential $(\Delta V_g)$ at a constant plate potential $(V_p)$.$g_m = \left( \frac{\Delta I_p}{\Delta V_g} ight)_{V_p = 	ext{constant}}$From the given graph, consider the curve for $V_p = 80 	ext{ V}$.At $V_g = 0 	ext{ V}$, $I_p = 20 	ext{ mA}$.At $V_g = -2 	ext{ V}$, $I_p = 0 	ext{ mA}$.Therefore, $\Delta I_p = (20 - 0) 	ext{ mA} = 20 	imes 10^{-3} 	ext{ A}$.And $\Delta V_g = (0 - (-2)) 	ext{ V} = 2 	ext{ V}$.$g_m = \frac{20 	imes 10^{-3} 	ext{ A}}{2 	ext{ V}} = 10 	imes 10^{-3} 	ext{ mho} = 10 	ext{ m mho}$.Wait, re-evaluating the slope between two points on the same curve:For $V_p = 80 	ext{ V}$, the linear region slope is $\frac{20 - 0}{0 - (-2)} = 10 	ext{ m mho}$.However, looking at the provided solution in the prompt, it uses $\frac{20-15}{4-2}$. Let's re-examine the graph. The points $(0, 20)$ and $(-2, 0)$ are on the $V_p = 80 	ext{ V}$ curve. The slope is $10 	ext{ m mho}$.Given the options, $10$ is the correct value.

The variation of anode current $(I_p)$ in a triode corresponding to a change in grid potential $(V_g)$ at three different values of the plate potential $(V_p)$ is shown in the diagram. The mutual conductance $(g_m)$ of the triode is.........$ m \text{ mho}$.

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