The velocity of a particle is given by $v = 2t^2 - 8t + 15 \,ms^{-1}$. Find its instantaneous acceleration at $t = 5 \,s$. (in $\,ms^{-2}$)

The position of a particle moving along the $X-$axis at certain times is given below. Which of the following describes the motion correctly?

$t (s)$	$0$	$1$	$2$	$3$
$x (m)$	$-2$	$0$	$6$	$16$

$A$ body starts from the origin and moves along the $x$-axis such that its position at any instant is $x = 4t^2 - 12t$,where $t$ is in seconds and $x$ is in meters. What is the acceleration of the particle in $m/s^2$?

The acceleration versus time graph of a body starting from rest is shown in the figure. The velocity versus time graph of the body is given by:

If the displacement ($s$ in metre) of a moving particle in terms of time ($t$ in second) is $s = t^3 - 6t^2 + 18t + 9$,then the minimum velocity attained by the particle is (in $m \ s^{-1}$)

$A$ particle moves along the $x$-axis and its displacement $x$ varies with time $t$ according to the equation $x = c_0(t^2 - 2) + c(t - 2)^2$,where $c_0$ and $c$ are constants of appropriate dimensions. Which of the following statements is correct?