The velocity of light in air is $3 \times 10^8 \, ms^{-1}$ and that in water is $2.2 \times 10^8 \, ms^{-1}$. The polarising angle of incidence is.......$^o$

The angle of polarisation for a medium with respect to air is $60^{\circ}$. The critical angle of this medium with respect to air is

The Brewster angle for air to glass transition of light is (Refractive index of glass $= 1.5$).

$A$ person lives in a high-rise building at a height of $30 \ m$ on the bank of a river. Across the river is a well-lit tower of height $60 \ m$. When the person looks through a polarizer at an appropriate angle at light from the top of the tower reflecting from the river surface,he finds the intensity of light is least. If the refractive index of water is $\frac{4}{3}$,the width of the river is ...... $m$.

An unpolarised light beam strikes a glass surface at Brewster's angle. Then

Given below are two statements:
Statement $I$: If the Brewster's angle for the light propagating from air to glass is $\theta_B$,then Brewster's angle for the light propagating from glass to air is $\frac{\pi}{2} - \theta_B$.
Statement $II$: The Brewster's angle for the light propagating from glass to air is $\tan^{-1}(\mu_g)$ where $\mu_g$ is the refractive index of glass.
In the light of the above statements,choose the correct answer from the options given below: