The velocity-time graph of an object moving a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The distance covered by an object is equal to the area under the velocity-time graph.To find the distance between $t = 0 \; s$ and $t = 4 \; s$,we

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(A) The distance covered by an object is equal to the area under the velocity-time graph.To find the distance between $t = 0 \; s$ and $t = 4 \; s$,we calculate the area of the region under the graph from $t = 0$ to $t = 4$.This region consists of a triangle from $t = 0$ to $t = 2$ and a rectangle from $t = 2$ to $t = 4$.Area of triangle (from $t = 0$ to $t = 2$) $= \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 2 \; s 	imes 10 \; m/s = 10 \; m$.Area of rectangle (from $t = 2$ to $t = 4$) $= 	ext{length} 	imes 	ext{width} = (4 - 2) \; s 	imes 10 \; m/s = 2 \; s 	imes 10 \; m/s = 20 \; m$.Total distance $= 10 \; m + 20 \; m = 30 \; m$.

The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance (in $m$) covered by the object between $t = 0$ and $t = 4 \; s$?

Similar Questions

If the position-time graph of a moving object is a straight line,determine the acceleration and velocity at any point.

If a steel ball is dropped from a height onto a marble floor,what will the velocity-time graph look like?

$A$ car starts from rest and moves with uniform acceleration $a$ on a straight road from time $t = 0$ to $t = T$. After that,a constant deceleration $a$ brings it to rest. In this process,the average speed of the car is

The displacement of the particle varies with time according to the relation $x = \frac{k}{b}\,[1 - {e^{ - bt}}]$. Then the velocity of the particle is

The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in $6 \, s$ are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module