The volume of a right circular cone is 1232, | vedclass

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(B) Let the radius of the cone be $r\, cm$.Given,volume $V = \frac{1}{3} \pi r^2 h = 1232\, cm^3$ and height $h = 24\, cm$.Substituting the values: $\

Vedclass · Accepted Answer

$550$

Vedclass · Answer

(B) Let the radius of the cone be $r\, cm$.Given,volume $V = \frac{1}{3} \pi r^2 h = 1232\, cm^3$ and height $h = 24\, cm$.Substituting the values: $\frac{1}{3} 	imes \frac{22}{7} 	imes r^2 	imes 24 = 1232$.$r^2 = \frac{1232 	imes 3 	imes 7}{22 	imes 24} = 49$.Therefore,$r = \sqrt{49} = 7\, cm$.Now,find the slant height $l = \sqrt{h^2 + r^2} = \sqrt{24^2 + 7^2} = \sqrt{576 + 49} = \sqrt{625} = 25\, cm$.The curved surface area of the cone is given by $A = \pi rl$.$A = \frac{22}{7} 	imes 7 	imes 25 = 550\, cm^2$.

The volume of a right circular cone is $1232\, cm^3$ and its vertical height is $24\, cm$. Its curved surface area is.......$cm^2$.

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