The wave pattern on a stretched string is shown in the figure. Interpret what kind of wave this is and find its wavelength.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The given figure shows a standing wave (or stationary wave) because the nodes (points with zero displacement) remain fixed at specific positions $x = 10, 20, 30, 40 \text{ cm}$ for all times $t$.
The distance between two consecutive nodes is equal to $\frac{\lambda}{2}$.
From the figure,the distance between two consecutive nodes is:
$\frac{\lambda}{2} = 20 \text{ cm} - 10 \text{ cm} = 10 \text{ cm}$.
Therefore,the wavelength $\lambda$ is:
$\lambda = 2 \times 10 \text{ cm} = 20 \text{ cm}$.

Explore More

Similar Questions

The pattern of standing waves formed on a stretched string at two instants of time is shown in the figure. The velocity of the two waves superimposing to form stationary waves is $360 \ m/s$ and their frequencies are $256 \ Hz$.
$(a)$ Calculate the time at which the second curve is plotted.
$(b)$ Mark nodes and antinodes on the curve.
$(c)$ Calculate the distance between $A^{\prime}$ and $C^{\prime}$.

What are stationary waves? Obtain their equation.

Energy is not carried by which of the following waves?

Which of the following statements is incorrect for a stationary wave?

The equation $y = 0.15 \sin(5x) \cos(300t)$ describes a stationary wave. The wavelength of the stationary wave is .... $m$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo