The wavelength of a photon with energy 35 tex | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given:Energy $E = 35 	ext{ keV} = 35 	imes 10^{3} 	imes 1.6 	imes 10^{-19} 	ext{ J} = 56 	imes 10^{-16} 	ext{ J}$.Using the formula for the

Vedclass · Accepted Answer

$35 	imes 10^{-12} 	ext{ m}$

Vedclass · Answer

(A) Given:Energy $E = 35 	ext{ keV} = 35 	imes 10^{3} 	imes 1.6 	imes 10^{-19} 	ext{ J} = 56 	imes 10^{-16} 	ext{ J}$.Using the formula for the wavelength of a photon:$E = \frac{hc}{\lambda} \implies \lambda = \frac{hc}{E}$Substituting the values:$\lambda = \frac{6.625 	imes 10^{-34} 	imes 3 	imes 10^{8}}{35 	imes 10^{3} 	imes 1.6 	imes 10^{-19}}$$\lambda = \frac{19.875 	imes 10^{-26}}{56 	imes 10^{-16}}$$\lambda \approx 0.3549 	imes 10^{-10} 	ext{ m} \approx 0.355 	imes 10^{-10} 	ext{ m} = 35.5 	imes 10^{-12} 	ext{ m}$.Rounding to the nearest provided option,the correct value is $35 	imes 10^{-12} 	ext{ m}$.

The wavelength of a photon with energy $35 \text{ keV}$ is . . . . . . .
$(h = 6.625 \times 10^{-34} \text{ J s}, c = 3 \times 10^{8} \text{ m/s}, 1 \text{ eV} = 1.6 \times 10^{-19} \text{ J})$

Similar Questions

$A$ $160 \,W$ light source is radiating light of wavelength $6200 \,\mathring A$ uniformly in all directions. The photon flux at a distance of $1.8 \,m$ is of the order of .......... $m^{-2} s^{-1}$ (Planck's constant $= 6.63 \times 10^{-34} \,J \cdot s$)

How is the intensity of radiation determined?

Find the number of photons emitted per second by a $100 \ W$ bulb emitting light of wavelength $540 \ nm$. (Given: $h = 6 \times 10^{-34} \ J \cdot s$)

In pair annihilation,an electron and a positron destroy each other to produce gamma radiation. How is the momentum conserved?

There are $n_1$ photons of frequency $\nu_1$ in a beam of light. In an equally energetic beam,there are $n_2$ photons of frequency $\nu_2$. Then the correct relation is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The wavelength of a photon with energy $35 \text{ keV}$ is . . . . . . .$(h = 6.625 \times 10^{-34} \text{ J s}, c = 3 \times 10^{8} \text{ m/s}, 1 \text{ eV} = 1.6 \times 10^{-19} \text{ J})$