The wavelength of light absorbed for the foll | vedclass

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(D) The wavelength of light absorbed $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.
$\lambda \propto \frac

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$III < I < IV < II < V$

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(D) The wavelength of light absorbed $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.
$\lambda \propto \frac{1}{\Delta_o}$
According to the spectrochemical series, the strength of ligands is: $F^{-} < H_2O < NH_3 < CN^{-}$.
The crystal field splitting energy $(\Delta_o)$ order for the given complexes is: $[CoF_6]^{3-} < [Co(H_2O)_6]^{3+} < [Co(NH_3)_5(H_2O)]^{3+} < [Co(NH_3)_6]^{3+} < [Co(CN)_6]^{3-}$.
Since $\lambda$ is inversely proportional to $\Delta_o$, the order of wavelength of light absorbed is: $V < II < IV < I < III$.
Therefore, the correct order of increasing wavelength is: $III < I < IV < II < V$.

The wavelength of light absorbed for the following complexes are in the order:
$I: [Co(NH_3)_6]^{3+}; II: [Co(H_2O)_6]^{3+}; III: [Co(CN)_6]^{3-}; IV: [Co(NH_3)_5(H_2O)]^{3+}; V: [CoF_6]^{3-}$

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The wavelength of light absorbed for the following complexes are in the order: $I: [Co(NH_3)_6]^{3+}; II: [Co(H_2O)_6]^{3+}; III: [Co(CN)_6]^{3-}; IV: [Co(NH_3)_5(H_2O)]^{3+}; V: [CoF_6]^{3-}$