The wavelength of the matter wave is independ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The wavelength of a matter wave (de Broglie wavelength) is given by the formula:$\lambda = \frac{h}{mv} = \frac{h}{p}$ $....(i)$where $h$ is Planc

Vedclass · Accepted Answer

Charge

Vedclass · Answer

(D) The wavelength of a matter wave (de Broglie wavelength) is given by the formula:$\lambda = \frac{h}{mv} = \frac{h}{p}$ $....(i)$where $h$ is Planck's constant,$m$ is the mass of the particle,$v$ is its velocity,and $p$ is its momentum.From equation $(i)$,it is clear that the wavelength $\lambda$ depends on the mass,velocity,and momentum of the particle.It does not depend on the charge of the particle.Therefore,the correct option is $D$.

The wavelength of the matter wave is independent of

Similar Questions

An $\alpha$-particle and a proton are accelerated from rest by the same potential. The ratio of their de-Broglie wavelengths is . . . . . .

The speed of a proton is $c / 20$. What will be the de Broglie wavelength associated with it?

The wavelength of a de-Broglie wave is $2 \mu m$. Calculate its momentum. (Given: $h = 6.63 \times 10^{-34} \ J \cdot s$)

What is the energy of a neutron with a de Broglie wavelength of $1 \ \mathring{A}$?

The ratio of the de-Broglie wavelengths of a proton and an electron having the same kinetic energy is: (Assume $m_p = 1849 \times m_e$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module