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(D) The multiples of $3$ between $1$ and $50$ form an Arithmetic Progression $(A.P.)$ as follows:$3, 6, 9, \ldots, 48$Here,the first term $a = 3$,the

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$16$

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(D) The multiples of $3$ between $1$ and $50$ form an Arithmetic Progression $(A.P.)$ as follows:$3, 6, 9, \ldots, 48$Here,the first term $a = 3$,the common difference $d = 3$,and the last term $T_n = 48$.Using the formula for the $n^{th}$ term of an $A.P.$:$T_n = a + (n - 1)d$Substituting the values:$48 = 3 + (n - 1)3$$48 - 3 = (n - 1)3$$45 = (n - 1)3$$n - 1 = \frac{45}{3}$$n - 1 = 15$$n = 16$Thus,there are $16$ multiples of $3$ between $1$ and $50$.

There are $\ldots \ldots \ldots \ldots$ multiples of $3$ lying between $1$ and $50$.

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