There is a frill of 20 bulbs connected in ser | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The light will increase.In a series circuit,the total resistance $R$ is the sum of the resistances of individual bulbs $(R = R_1 + R_2 + ... + R_{

Vedclass · Accepted Answer

Increase

Vedclass · Answer

(A) The light will increase.In a series circuit,the total resistance $R$ is the sum of the resistances of individual bulbs $(R = R_1 + R_2 + ... + R_{20})$.The power consumed by the circuit is given by the formula $P = \frac{V^2}{R}$,where $V$ is the supply voltage and $R$ is the total resistance.When one bulb is removed (or fused),the total resistance of the circuit decreases because there are now only $19$ bulbs in series.Since the power $P$ is inversely proportional to the resistance $R$ $(P \propto \frac{1}{R})$,a decrease in total resistance leads to an increase in the total power consumed by the remaining bulbs.Therefore,the brightness of the light in the room will increase.

There is a frill of $20$ bulbs connected in series in a room. One bulb gets fused. The remaining $19$ are again joined in series and connected to the same supply. Will the light increase or decrease in the room?

Similar Questions

In the figure given below,$A, B$,and $C$ are three ammeters. The ammeter $B$ reads $0.5\, A$. (All the ammeters have negligible resistance.) Calculate:
$(i)$ the readings in the ammeters $A$ and $C$.
$(ii)$ the total resistance of the circuit.

What is the equivalent resistance of a circuit when three resistors of $5 \Omega$,$10 \Omega$,and $30 \Omega$ are connected in parallel (in $\Omega$)?

When do we say that the resistors are connected in series?

What is meant by equivalent resistance?

The equivalent resistance between points $A$ and $B$ in the following electric circuit is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module