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(D) When resistors are connected in parallel,the equivalent resistance $(R_{eq})$ is given by the formula: $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1

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$3$

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(D) When resistors are connected in parallel,the equivalent resistance $(R_{eq})$ is given by the formula: $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$ Given $R_1 = 5 \Omega$,$R_2 = 10 \Omega$,and $R_3 = 30 \Omega$. Substituting these values into the formula: $\frac{1}{R_{eq}} = \frac{1}{5} + \frac{1}{10} + \frac{1}{30}$ To add these fractions,find the least common multiple $(LCM)$ of $5, 10,$ and $30$,which is $30$. $\frac{1}{R_{eq}} = \frac{6}{30} + \frac{3}{30} + \frac{1}{30} = \frac{10}{30} = \frac{1}{3}$ Therefore,$R_{eq} = 3 \Omega$.

What is the equivalent resistance of a circuit when three resistors of $5 \Omega$,$10 \Omega$,and $30 \Omega$ are connected in parallel (in $\Omega$)?

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