Three capacitors of $2.0\;\mu F$,$3.0\;\mu F$,and $6.0\;\mu F$ are connected in series to a $10\,V$ source. The charge on the $3.0\;\mu F$ capacitor is ........ $\mu C$.

Seven capacitors,each of capacitance $2\,\mu F$,are to be connected in a configuration to obtain an effective capacitance of $\left( \frac{6}{13} \right)\,\mu F$. Which of the combinations,shown in figures below,will achieve the desired value?

The difference between the equivalent capacitances of two identical capacitors connected in parallel and in series is $6 \mu F$. The value of the capacitance of each capacitor is (in $\mu F$)

$A$ parallel combination of two capacitors of capacities $2C$ and $C$ is connected across a $5 \text{ V}$ battery. When they are fully charged,the charges and energies stored in them are $Q_1, Q_2$ and $E_1, E_2$ respectively. Then $\frac{E_1-E_2}{Q_1-Q_2}$ in $\text{J/C}$ is (capacity is in Farad,charge in Coulomb and energy in $\text{J}$)

Three condensers of capacities $C_1$,$C_2$,and $C_3$ are connected in series with a source of e.m.f. $V$. The potentials across the three condensers are in the ratio:

Two capacitors of capacitance $2 \mu F$ and $4 \mu F$ respectively are connected in series. The combination is connected across a potential difference of $10 \ V$. The ratio of energies stored by the capacitors will be . . . . . . .