Three capacitors of capacitance $C$ ($\mu F$) are connected in parallel, and this combination is connected in series with another capacitor of capacitance $C$. If the effective capacitance is $3.75 \mu F$, then the capacity of each capacitor is: (in $\mu F$)

What is a series connection of capacitors? Obtain the formula for the effective capacitance in the series combination of two different capacitors.

How will you connect four capacitors,each of capacitance $4 \mu F$,to obtain an equivalent capacitance of $1.6 \mu F$?

In the given circuit,a charge of $+80 \ \mu C$ is given to the upper plate of the $4 \ \mu F$ capacitor. Then in the steady state,the charge on the upper plate of the $3 \ \mu F$ capacitor is:

The combination of capacitors with $C_1 = 3\,\mu F$,$C_2 = 4\,\mu F$,and $C_3 = 2\,\mu F$ is charged by connecting $A$ and $B$ to a battery. Consider the following statements:
$I.$ Energy stored in $C_1$ $=$ Energy stored in $C_2$ $+$ Energy stored in $C_3$
$II.$ Charge on $C_1$ $=$ Charge on $C_2$ $+$ Charge on $C_3$
$III.$ Potential drop across $C_1$ $=$ Potential drop across $C_2$ $=$ Potential drop across $C_3$
Which of these is/are correct?

The equivalent capacitance between points $A$ and $B$ is