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(A) From the given circuit diagram,the capacitors $3 C$ and $2 C$ are connected in parallel between the same two nodes.Therefore,their equivalent capa

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$\frac{5}{6} C$

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(A) From the given circuit diagram,the capacitors $3 C$ and $2 C$ are connected in parallel between the same two nodes.Therefore,their equivalent capacitance $C_p$ is given by:$C_p = 3 C + 2 C = 5 C$Now,this equivalent capacitor $C_p = 5 C$ is in series with the capacitor $C$.The total equivalent capacitance $C_{AB}$ between points $A$ and $B$ is given by the series formula:$C_{AB} = \frac{C 	imes C_p}{C + C_p} = \frac{C 	imes 5 C}{C + 5 C} = \frac{5 C^2}{6 C} = \frac{5}{6} C$

The equivalent capacitance between points $A$ and $B$ is

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