In the circuit shown in the figure,the batter | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The two capacitors $C$ and $2C$ are connected in series across the $10 \ V$ battery.The equivalent capacitance $C_{eq}$ of two capacitors in serie

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(C) The two capacitors $C$ and $2C$ are connected in series across the $10 \ V$ battery.The equivalent capacitance $C_{eq}$ of two capacitors in series is given by:$C_{eq} = \frac{C 	imes 2C}{C + 2C} = \frac{2C^2}{3C} = \frac{2}{3}C$Given $C = 6 \ \mu F$,the equivalent capacitance is:$C_{eq} = \frac{2}{3} 	imes 6 \ \mu F = 4 \ \mu F$The total charge $q$ drawn from the battery is:$q = C_{eq} 	imes V = 4 \ \mu F 	imes 10 \ V = 40 \ \mu C$Since the capacitors are in series,the same amount of charge $q$ is stored on each capacitor. Therefore,the charge stored in the capacitor of capacity $C$ is $40 \ \mu C$.

In the circuit shown in the figure,the battery is $10 \ V$ and $C = 6 \ \mu F$. The charge stored in the capacitor of capacity $C$ is......$\mu C$.

Similar Questions

The potential difference across the $4 \mu F$ capacitor in series with the parallel combination in the following circuit is: (in $V$)

The capacitors of capacity $C_1$ and $C_2$ are connected in parallel,then the equivalent capacitance is:

Six identical square metallic plates are arranged as shown in the figure. The length of each plate is $l$. The equivalent capacitance of this arrangement would be . . . . . . .

Two capacitances of capacity $C_1$ and $C_2$ are connected in series and a potential difference $V$ is applied across the combination. The potential difference across $C_1$ will be:

Ten capacitors are connected in parallel to a battery of $V$ volts. If all capacitors are disconnected from the battery and then connected in series,what will be the voltage across the combination in terms of $V$ (in $V$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module