The capacitors of capacity $C_1$ and $C_2$ are connected in parallel,then the equivalent capacitance is:

Two capacitors of capacitance $4\,\mu F$ and $6\,\mu F$ are connected in series. $A$ potential difference of $500\;V$ is applied to the outer plates of the two-capacitor system. The charge on each capacitor is numerically:

Three capacitors each of capacitance $C$ and breakdown voltage $V$ are connected in series. The capacitance and breakdown voltage of the series combination will be respectively:

Five capacitors,each of value $1 \mu F$,are connected as shown in the figure. The equivalent capacitance between $A$ and $B$ is (in $\mu F$)

Three capacitors of capacitances $2 \;pF$,$3 \;pF$,and $4 \;pF$ are connected in parallel.
$(a)$ What is the total capacitance of the combination?
$(b)$ Determine the charge on each capacitor if the combination is connected to a $100 \;V$ supply.

Four capacitors are connected as shown in the figure. The equivalent capacitance between the points $P$ and $Q$ is ....... $\mu F$.