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(C) When three fair coins are tossed,the sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$.Since the condition is that both heads and t

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$\frac{1}{2}$

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(C) When three fair coins are tossed,the sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$.Since the condition is that both heads and tails appear,we exclude the cases $HHH$ and $TTT$.Thus,the reduced sample space $S'$ is $\{HHT, HTH, THH, HTT, THT, TTH\}$,so $n(S') = 6$.Let $E$ be the event that exactly one head appears. The outcomes in $E$ are $\{HTT, THT, TTH\}$,so $n(E) = 3$.The required probability is $P(E) = \frac{n(E)}{n(S')} = \frac{3}{6} = \frac{1}{2}$.

Three fair coins are tossed. If both heads and tails appear,then the probability that exactly one head appears is:

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