Three identical p-n junction diodes D_1, D_2 | vedclass

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(C) $1$. Analyze the biasing of each diode:- Diode $D_1$ is forward-biased because its p-side is connected to the positive terminal of the battery.- D

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$W_3 > W_2 > W_1$

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(C) $1$. Analyze the biasing of each diode:- Diode $D_1$ is forward-biased because its p-side is connected to the positive terminal of the battery.- Diode $D_2$ is in an open circuit (due to the gap in the wire), so no current flows through it. It acts as an unbiased diode.- Diode $D_3$ is reverse-biased because its n-side is connected to the positive terminal of the battery.$2$. Relate bias to depletion width:- Forward bias reduces the depletion width $(W_f - Unbiased state has a standard depletion width $(W_0)$.- Reverse bias increases the depletion width $(W_r > W_0)$.$3$. Compare the widths:- For $D_1$ (forward-biased): $W_1$ is minimum.- For $D_2$ (unbiased): $W_2$ is intermediate.- For $D_3$ (reverse-biased): $W_3$ is maximum.Therefore, $W_3 > W_2 > W_1$.

Three identical p-n junction diodes $D_1$, $D_2$ and $D_3$ are connected across a battery as shown in the figure. If the widths of the depletion regions of $D_1$, $D_2$ and $D_3$ are $W_1$, $W_2$ and $W_3$, respectively, then the correct option is:

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